1.21: Normal to a square-root curve

0606/11/O/N/19 — Question 6 · 5 marks

Find the equation of the normal to the curve y=8x+5y = \sqrt{8x + 5} at the point where x=12x = \dfrac{1}{2}, giving your answer in the form ax+by+c=0ax + by + c = 0, where aa, bb and cc are integers.
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