Additional Mathematics 0606 / Calculus — Differentiation 1 / 1.211.21: Normal to a square-root curve0606/11/O/N/19 — Question 6 · 5 marksMark as done · Save for later · Show all solutionsFind the equation of the normal to the curve y=8x+5y = \sqrt{8x + 5}y=8x+5 at the point where x=12x = \dfrac{1}{2}x=21, giving your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where aaa, bbb and ccc are integers.[5]▸ Answer▸ Official mark scheme← 1.20: Quotient rule and approximate change1.52: Product rule and related rates →