Additional Mathematics 0606 / Calculus — Differentiation 1 / 1.351.35: Stationary point of a quotient with a square root0606/12/M/J/18 — Question 6 · 6 marksMark as done · Save for later · Show all solutionsFind the coordinates of the stationary point of the curve y=x+22x−1y = \dfrac{x + 2}{\sqrt{2x - 1}}y=2x−1x+2.[6]▸ Answer▸ Official mark scheme← 2.75: Tangents to a quadratic curve2.7: Product and quotient rule differentiation →
