Additional Mathematics 0606 / Calculus — Differentiation 1 / 1.601.60: Normal intercepts and midpoint0606/13/M/J/17 — Question 5 · 7 marksMark as done · Save for later · Show all solutionsThe normal to the curve y=4x+9y = \sqrt{4x + 9}y=4x+9, at the point where x=4x = 4x=4, meets the xxx- and yyy-axes at the points AAA and BBB. Find the coordinates of the mid-point of the line ABABAB.[7]▸ Answer▸ Official mark scheme← 1.31: Quotient rule with a square-root numerator1.63: Stationary point and small increments →