Additional Mathematics 0606 / Calculus — Differentiation 1 / 2.342.34: Normal to a quadratic curve0606/22/M/J/17 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsThe point PPP lies on the curve y=3x2−7x+11y = 3x^{2} - 7x + 11y=3x2−7x+11. The normal to the curve at PPP has equation 5y+x=k5y + x = k5y+x=k. Find the coordinates of PPP and the value of kkk.[6]▸ Answer▸ Official mark scheme← 1.63: Stationary point and small increments2.17: Tangent to a cubic and second intersection →