3.5: Tangent to a cubic and inverse-function gradient

0606/22/F/M/21 — Question 7 · 8 marks

A curve has equation y=p(x)y = p(x), where p(x)=x34x2+6x1p(x) = x^{3} - 4x^{2} + 6x - 1.
(a)
Find the equation of the tangent to the curve at the point (3,8)(3, 8). Give your answer in the form y=mx+cy = mx + c.
[5]
(b)(i)
Given that p1p^{-1} exists, write down the gradient of the tangent to y=p1(x)y = p^{-1}(x) at (8,3)(8, 3).
[1]
(b)(ii)
Find the coordinates of the point of intersection of these two tangents.
[2]