Additional Mathematics 0606 / Calculus — Differentiation 1 / 3.253.25: Small change relating x and y0606/22/M/J/22 — Question 4 · 5 marksMark as done · Save for later · Show all solutionsVariables xxx and yyy are related by y=x+1x+2y = x + \dfrac{1}{x} + 2y=x+x1+2 where x>0x > 0x>0. Use differentiation to find the approximate change in xxx when yyy increases from 444 by the small amount 0.010.010.01.[5]▸ Answer▸ Official mark scheme← 3.92: Approximate change using differentiation3.6: Differentiation, small increments and connected rates →