Additional Mathematics 0606 / Calculus — Differentiation 1 / 3.433.43: Related rates for a sphere0606/22/M/J/25 — Question 5 · 4 marksMark as done · Save for later · Show all solutionsThe volume VVV of a sphere is increasing at the constant rate of π cm3s−1\pi\,\mathrm{cm}^{3}\mathrm{s}^{-1}πcm3s−1. Find the rate of change of the surface area SSS when the volume is 36π cm336\pi\,\mathrm{cm}^{3}36πcm3.[4]▸ Answer▸ Official mark scheme← 3.90: Small change for y=sin5xy = \sin 5xy=sin5x3.58: Derivative, small change and stationary point →