Additional Mathematics 0606 / Calculus — Differentiation 1 / 3.553.55: Normal to a cubic curve0606/22/O/N/23 — Question 4 · 5 marksMark as done · Save for later · Show all solutions(a)Find the equation of the normal to the curve y=7x3−12x2+5x−1y = 7x^{3} - 12x^{2} + 5x - 1y=7x3−12x2+5x−1 at the point (1, 1)(1,\ 1)(1, 1).[5]▸ Answer▸ Official mark scheme← 3.54: Non-zero k for a tangent condition3.29: Completing the square, stationary point and sketch →
