1.16: Logarithmic curve: derivative and stationary point

0606/11/O/N/17 — Question 7 · 9 marks

A curve has equation y=ln(2x+12x1)+4xy = \ln\left(\dfrac{2x + 1}{2x - 1}\right) + 4x for x>12x > \dfrac{1}{2}.
(i)
Write ln(2x+12x1)\ln\left(\dfrac{2x + 1}{2x - 1}\right) as the difference of two logarithms.
[1]
(ii)
Using your answer to part (i) show that dydx=ax2+b4x21\dfrac{\mathrm{d}y}{\mathrm{d}x} = \dfrac{ax^{2} + b}{4x^{2} - 1}, where aa and bb are integers.
[4]
(iii)
Hence find the xx-coordinate of the stationary point on the curve.
[2]
(iv)
Determine the nature of this stationary point.
[2]