Additional Mathematics 0606 / Calculus — Differentiation 2 / 1.171.17: Quotient rule and tangent to a logarithmic rational curve0606/11/O/N/18 — Question 6 · 6 marksMark as done · Save for later · Show all solutionsA curve has the equation y=ln(2x2+3)5x+2y = \dfrac{\ln(2x^{2} + 3)}{5x + 2}y=5x+2ln(2x2+3).(i)Show that dydx=−54ln3\dfrac{\mathrm{d}y}{\mathrm{d}x} = -\dfrac{5}{4}\ln 3dxdy=−45ln3 when x=0x = 0x=0.[4]▸ Answer(ii)Hence find the equation of the tangent to the curve at the point where x=0x = 0x=0.[2]▸ Answer▸ Official mark scheme← 2.61: Product rule with tangent and cosine1.19: Exponential function and small changes →