1.79: Normal to a logarithmic quotient

0606/13/O/N/18 — Question 9 · 8 marks

Find the equation of the normal to the curve y=ln(3x2+1)x2y = \dfrac{\ln(3x^{2} + 1)}{x^{2}} at the point where x=2x = 2, giving your answer in the form y=mx+cy = mx + c, where mm and cc are correct to 2 decimal places. You must show all your working.
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