Additional Mathematics 0606 / Calculus — Differentiation 2 / 2.282.28: Logarithm of a trigonometric expression0606/21/O/N/20 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsIt is given that y=ln(sinx+3cosx)y = \ln(\sin x + 3\cos x)y=ln(sinx+3cosx) for 0<x<π20 < x < \tfrac{\pi}{2}0<x<2π.(a)Find dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}dxdy.[3]▸ Answer(b)Find the value of xxx for which dydx=−12\dfrac{\mathrm{d}y}{\mathrm{d}x} = -\tfrac{1}{2}dxdy=−21.[3]▸ Answer▸ Official mark scheme← 1.55: Normal to a logarithmic quotient2.78: Logarithmic trigonometric differentiation →
