3.70: Derivative of xcos2xx\mathrm{cos}\,2x; integrate xsin2xx\mathrm{sin}\,2x

0606/22/O/N/25 — Question 7 · 6 marks

(a)
Given that y=xcos2xy = x\mathrm{cos}\,2x, find dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}.
[2]
(b)
Hence find xsin2xdx\displaystyle\int x\mathrm{sin}\,2x\,\mathrm{d}x.
[4]