3.99: Tangent to exponential curve

0606/22/M/J/24 — Question 5 · 6 marks

A curve has equation y=5ex+e2xy = 5\mathrm{e}^{x} + \mathrm{e}^{-2x}. The tangent at x=1x = 1 cuts the xx-axis at PP. Find the equation of the tangent in the form y=mx+cy = mx + c and hence the xx-coordinate of PP.
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