Additional Mathematics 0606 / Calculus — Integration / 1.61.6: Finding the equation of a curve from a second derivative0606/11/M/J/18 — Question 12 · 8 marksMark as done · Save for later · Show all solutionsA curve is such that d2ydx2=(2x−5)−12\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = (2x - 5)^{-\frac{1}{2}}dx2d2y=(2x−5)−21. Given that the curve has a gradient of 666 at the point (92,23)\left(\dfrac{9}{2}, \dfrac{2}{3}\right)(29,32), find the equation of the curve.[8]▸ Answer▸ Official mark scheme← 1.5: Minimum point and area between curve and chord1.36: Area bounded by exponential curve and normal →