Additional Mathematics 0606 / Calculus — Integration / 1.231.23: Equation of a curve from a trigonometric second derivative0606/11/O/N/19 — Question 12 · 8 marksMark as done · Save for later · Show all solutionsA curve is such that d2ydx2=2sin(x+π3)\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = 2\sin\left(x + \dfrac{\pi}{3}\right)dx2d2y=2sin(x+3π). Given that the curve has a gradient of 555 at the point (π3,5π3)\left(\dfrac{\pi}{3}, \dfrac{5\pi}{3}\right)(3π,35π), find the equation of the curve.[8]▸ Answer▸ Official mark scheme← 1.22: Area between a cosine curve and a horizontal line1.54: Finding a curve from second derivative →