1.62: Product rule and integration of a logarithm

0606/13/M/J/17 — Question 10 · 9 marks

It is given that y=(10x+2)ln(5x+1)y = (10x + 2)\ln(5x + 1).
(i)
Find dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}.
[4]
(ii)
Hence show that ln(5x+1)dx=(ax+b)5ln(5x+1)x+c\displaystyle\int \ln(5x + 1)\,\mathrm{d}x = \frac{(ax + b)}{5}\ln(5x + 1) - x + c, where aa and bb are integers and cc is a constant of integration.
[3]
(iii)
Hence find 015ln(5x+1)dx\displaystyle\int_{0}^{\frac{1}{5}} \ln(5x + 1)\,\mathrm{d}x, giving your answer in the form d+lnf5\dfrac{d + \ln f}{5}, where dd and ff are integers.
[2]