Additional Mathematics 0606 / Calculus — Integration / 1.661.66: Finding a curve from a fractional second derivative0606/13/M/J/18 — Question 12 · 8 marksMark as done · Save for later · Show all solutionsA curve is such that d2ydx2=(2x−5)−12\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = (2x - 5)^{-\frac{1}{2}}dx2d2y=(2x−5)−21. Given that the curve has a gradient of 666 at the point (92,23)\left(\dfrac{9}{2}, \dfrac{2}{3}\right)(29,32), find the equation of the curve.[8]▸ Answer▸ Official mark scheme← 1.65: Minimum point and area between curve and chord2.37: Differentiating and integrating with square roots of sine →