Additional Mathematics 0606 / Calculus — Integration / 1.751.75: Power integration and solving for a limit0606/13/O/N/17 — Question 5 · 5 marksMark as done · Save for later · Show all solutions(i)Find ∫(7x−10)−35 dx\displaystyle\int (7x - 10)^{-\frac{3}{5}}\,\mathrm{d}x∫(7x−10)−53dx.[2]▸ Answer(ii)Given that ∫6a(7x−10)−35 dx=2514\displaystyle\int_{6}^{a} (7x - 10)^{-\frac{3}{5}}\,\mathrm{d}x = \frac{25}{14}∫6a(7x−10)−53dx=1425, find the exact value of aaa.[3]▸ Answer▸ Official mark scheme← 1.74: Finding a curve from an exponential gradient2.20: Differentiation leading to integration →
