Additional Mathematics 0606 / Calculus — Integration / 2.212.21: Finding y from a second derivative0606/21/O/N/17 — Question 7 · 6 marksMark as done · Save for later · Show all solutionsFind yyy in terms of xxx, given that d2ydx2=6x+2x3\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = 6x + \dfrac{2}{x^{3}}dx2d2y=6x+x32 and that when x=1x = 1x=1, y=3y = 3y=3 and dydx=1\dfrac{\mathrm{d}y}{\mathrm{d}x} = 1dxdy=1.[6]▸ Answer▸ Official mark scheme← 2.20: Differentiation leading to integration2.48: Curve from normal gradient and tangent equation →
