Additional Mathematics 0606 / Calculus — Integration / 2.732.73: Integration from a second derivative0606/23/O/N/18 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsIt is given that d2ydx2=2x+3(x+1)4\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = 2x + \dfrac{3}{(x+1)^{4}}dx2d2y=2x+(x+1)43.(i)Find dydx\dfrac{\mathrm{d}y}{\mathrm{d}x}dxdy, given that dydx=1\dfrac{\mathrm{d}y}{\mathrm{d}x} = 1dxdy=1 when x=1x = 1x=1.[3]▸ Answer(ii)Find yyy in terms of xxx, given that y=3y = 3y=3 when x=1x = 1x=1.[3]▸ Answer▸ Official mark scheme← 2.53: Normal to a square-root curve and shaded area1.5: Minimum point and area between curve and chord →
