Additional Mathematics 0606 / Calculus — Integration / 3.73.7: Finding f(x) from a second derivative0606/12/F/M/22 — Question 7 · 8 marksMark as done · Save for later · Show all solutionsA curve y=f(x)y = f(x)y=f(x) is such that d2ydx2=(2−3x)−13\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = (2 - 3x)^{-\frac{1}{3}}dx2d2y=(2−3x)−31. The curve passes through (−2, 10.2)(-2,\ 10.2)(−2, 10.2) and the gradient there is −6-6−6.Find f(x)f(x)f(x).[8]▸ Answer▸ Official mark scheme← 3.76: Partial fractions integration3.87: Find f(x)f(x)f(x) from a derivative and a point →
