Additional Mathematics 0606 / Calculus — Integration / 3.563.56: Normal intersecting a cubic again; definite integral0606/22/O/N/23 — Question 5 · 10 marksMark as done · Save for later · Show all solutions(a)Find the equation of the normal to y=7x3−12x2+5x−1y = 7x^{3} - 12x^{2} + 5x - 1y=7x3−12x2+5x−1 at (1, 1)(1,\ 1)(1, 1).[5]▸ Answer(b)Find the xxx-coordinates of the two points where the normal cuts the curve again, in the form x=a±bx = a \pm bx=a±b.[5]▸ Answer▸ Official mark scheme← 3.11: Exact area under an exponential curve3.85: Area between curve and line; integrals →
