3.69: Integrals involving exponential, reciprocal and sec

0606/23/O/N/25 — Question 4 · 7 marks

(a)(i)
Integrate e52x\mathrm{e}^{5 - 2x} with respect to xx.
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(a)(ii)
Integrate (4x3)1(4x - 3)^{-1} with respect to xx, where x>34x > \dfrac{3}{4}.
[2]
(b)
Show that π/6π/3sec2xdx=23\displaystyle\int_{\pi/6}^{\pi/3}\sec^{2} x\,\mathrm{d}x = \dfrac{2}{\sqrt{3}}.
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