3.83: Second-order differential equation of a curve

0606/21/M/J/21 — Question 9 · 7 marks

A curve is such that d2ydx2=sin(6xπ2)\dfrac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = \sin\left(6x - \dfrac{\pi}{2}\right). Given that dydx=12\dfrac{\mathrm{d}y}{\mathrm{d}x} = \dfrac{1}{2} at the point (π4,13π12)\left(\dfrac{\pi}{4}, \dfrac{13\pi}{12}\right) on the curve, find the equation of the curve.
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