Additional Mathematics 0606 / Equations, inequalities and graphs / 1.31.3: Substitution to solve a fractional power equation0606/11/O/N/17 — Question 3 · 4 marksMark as done · Save for later · Show all solutions(b)By using the substitution y=x13y = x^{\frac{1}{3}}y=x31, or otherwise, solve x23−4x13+3=0x^{\frac{2}{3}} - 4x^{\frac{1}{3}} + 3 = 0x32−4x31+3=0.[4]▸ Answer▸ Official mark scheme← 2.19: Completing the square, modulus quadratic sketch and solutions2.7: Quadratic inequality from a product →
