Additional Mathematics 0606 / Equations, inequalities and graphs / 1.111.11: Cubic sketch and inequality0606/13/O/N/20 — Question 1 · 5 marksMark as done · Save for later · Show all solutions(a)On the axes below, sketch the graph of y=(x−2)(x+1)(3−x)y = (x - 2)(x + 1)(3 - x)y=(x−2)(x+1)(3−x), stating the intercepts on the coordinate axes.[3]▸ Answer(b)Hence write down the values of xxx such that (x−2)(x+1)(3−x)>0(x - 2)(x + 1)(3 - x) > 0(x−2)(x+1)(3−x)>0.[2]▸ Answer▸ Official mark scheme← 1.10: Cubic from a graph and inequality2.10: Modulus inequality →
