Additional Mathematics 0606 / Equations, inequalities and graphs / 2.112.11: Discriminant and quadratic inequality in kkk0606/22/M/J/16 — Question 1 · 4 marksMark as done · Save for later · Show all solutions(i)Given that x2+2kx+4k−3=0x^{2} + 2kx + 4k - 3 = 0x2+2kx+4k−3=0 has no real roots, show that kkk satisfies k2−4k+3<0k^{2} - 4k + 3 < 0k2−4k+3<0.[2]▸ Answer(ii)Solve the inequality k2−4k+3<0k^{2} - 4k + 3 < 0k2−4k+3<0.[2]▸ Answer▸ Official mark scheme← 2.1: Quadratic inequality from a product2.12: Exponential equations by substitution →