Additional Mathematics 0606 / Equations, inequalities and graphs / 3.1073.107: Modulus inequality and quadratic0606/21/M/J/21 — Question 3 · 6 marksMark as done · Save for later · Show all solutions(a)Solve the inequality ∣4x−1∣>9\lvert 4x - 1\rvert > 9∣4x−1∣>9.[3]▸ Answer(b)Solve the equation x2−11x+12=0x^{2} - 11x + 12 = 0x2−11x+12=0.[3]▸ Answer▸ Official mark scheme← 3.25: Complete the square and minimum point3.26: Sketch y=(3−x)(x−1)(x+2)y = (3 - x)(x - 1)(x + 2)y=(3−x)(x−1)(x+2) →
