Additional Mathematics 0606 / Equations, inequalities and graphs / 3.1083.108: Solve a cubic reciprocal equation0606/13/O/N/23 — Question 7 · 4 marksMark as done · Save for later · Show all solutionsSolve the equation x3−1x3=6(x−1x)x^{3} - \dfrac{1}{x^{3}} = 6\left(x - \dfrac{1}{x}\right)x3−x31=6(x−x1). Give your answers in exact form.[4]▸ Answer▸ Official mark scheme← 3.84: Linear and modulus graphs; inequality3.85: Solve an equation with 10\sqrt{10}10 →
