Additional Mathematics 0606 / Equations, inequalities and graphs / 3.143.14: Sketch graphs and solve a linear–modulus inequality0606/12/F/M/25 — Question 1 · 7 marksMark as done · Save for later · Show all solutions(a)On the axes, sketch the graphs of y=∣x−4∣y = |x - 4|y=∣x−4∣ and y=12x+3y = \dfrac{1}{2}x + 3y=21x+3, stating the intercepts with the axes.[3]▸ Answer(b)Solve the inequality ∣x−4∣⩾12x+3|x - 4| \geqslant \dfrac{1}{2}x + 3∣x−4∣⩾21x+3.[4]▸ Answer▸ Official mark scheme← 3.105: Square of a linear function: sketch and inequality3.15: Stationary points, sketch and number of roots →
