Additional Mathematics 0606 / Equations, inequalities and graphs / 3.293.29: Quadratic inequality and enclosed area0606/23/M/J/21 — Question 5 · 6 marksMark as done · Save for later · Show all solutions(a)Solve the inequality 2x2−17x+21⩽02x^{2} - 17x + 21 \leqslant 02x2−17x+21⩽0.[3]▸ Answer(b)Hence find the area enclosed between the curve y=2x2−17x+21y = 2x^{2} - 17x + 21y=2x2−17x+21 and the xxx-axis.[3]▸ Answer▸ Official mark scheme← 3.28: Solve for xxx in a given exponential expression3.102: Absolute-value quadratic: stationary point and sketch →
