Additional Mathematics 0606 / Equations, inequalities and graphs / 3.353.35: Inequality and distinct real roots0606/23/M/J/22 — Question 4 · 5 marksMark as done · Save for later · Show all solutions(a)Find the range of values of xxx satisfying the inequality (5x−1)(6−x)<0(5x - 1)(6 - x) < 0(5x−1)(6−x)<0.[2]▸ Answer(b)Show that the equation (2k+1)x2−4kx+(2k−1)=0(2k + 1)x^{2} - 4kx + (2k - 1) = 0(2k+1)x2−4kx+(2k−1)=0, where k≠−12k \neq -\tfrac{1}{2}k=−21, has distinct real roots.[3]▸ Answer▸ Official mark scheme← 3.34: Solve ∣4x−7∣=9−5x|4x - 7| = 9 - 5x∣4x−7∣=9−5x3.4: Combine fractions and integrate →
