3.41: Quadratic inequality and tangent at a minimum

0606/22/M/J/23 — Question 1 · 7 marks

(a)
Solve the inequality 3x212x+16>3x+43x^{2} - 12x + 16 > 3x + 4.
[3]
(b)(i)
Write 3x212x+163x^{2} - 12x + 16 in the form a(x+b)2+ca(x + b)^{2} + c where aa, bb and cc are integers.
[3]
(b)(ii)
Hence, write down the equation of the tangent to the curve y=3x212x+16y = 3x^{2} - 12x + 16 at the minimum point of the curve.
[1]