Additional Mathematics 0606 / Equations, inequalities and graphs / 3.483.48: Solve a quadratic in 3x3^{x}3x0606/13/M/J/24 — Question 2 · 4 marksMark as done · Save for later · Show all solutionsSolve the equation 32x−11⋅3x+18=03^{2x} - 11\cdot 3^{x} + 18 = 032x−11⋅3x+18=0, giving your answers correct to 2 decimal places where necessary.[4]▸ Answer▸ Official mark scheme← 3.47: Selecting a mixed team3.49: Stationary points, sketch and values of kkk →
