3.70: Cone volume maximisation with fixed curved surface

0606/21/O/N/21 — Question 11 · 11 marks

The volume, VV, of a cone with base radius rr and vertical height hh is given by 13πr2h\dfrac{1}{3}\pi r^{2} h. The curved surface area of a cone with base radius rr and slant height ll is given by πrl\pi r l.
A cone has base radius rcmr\,\mathrm{cm}, vertical height hcmh\,\mathrm{cm} and volume Vcm3V\,\mathrm{cm}^{3}. The curved surface area of the cone is 4πcm24\pi\,\mathrm{cm}^{2}.
(a)
Show that h2=16r2r2h^{2} = \dfrac{16}{r^{2}} - r^{2}.
[4]
(b)
Show that V=π316r2r6V = \dfrac{\pi}{3}\sqrt{16r^{2} - r^{6}}.
[2]
(c)
Given that rr can vary and that VV has a maximum value, find the value of rr that gives the maximum volume.
[5]