Additional Mathematics 0606 / Equations, inequalities and graphs / 3.773.77: Solve an equation in ex\mathrm{e}^{x}ex0606/22/O/N/22 — Question 2 · 4 marksMark as done · Save for later · Show all solutionsSolve the equation 4e2x−3=7e5−x4\mathrm{e}^{2x - 3} = 7\mathrm{e}^{5 - x}4e2x−3=7e5−x.[4]▸ Answer▸ Official mark scheme← 3.100: Completing the square and related equation3.78: Intersection of two polynomial curves →
