Additional Mathematics 0606 / Equations, inequalities and graphs / 4.074.07: Modulus graph and inequality0606/23/M/J/26 — Question 1 · 5 marksMark as done · Save for later · Show official mark scheme(a)On the grid, draw \(y=|2x+1|\) for \(-3\leqslant x\leqslant3\).[2]▸ AnswerSee the official mark scheme below.(b)By drawing a suitable straight line, solve \(|2x+1|>x+2\).[3]▸ AnswerSee the official mark scheme below.Official mark scheme unavailable in the supplied 2026 folder
