Additional Mathematics 0606 / Factors and polynomials / 1.21.2: Coefficients from a remainder and a derivative condition0606/11/M/J/17 — Question 2 · 5 marksMark as done · Save for later · Show all solutionsIt is given that p(x)=x3+ax2+bx−48p(x) = x^{3} + ax^{2} + bx - 48p(x)=x3+ax2+bx−48. When p(x)p(x)p(x) is divided by x−3x - 3x−3 the remainder is 6. Given that p′(1)=0p'(1) = 0p′(1)=0, find the value of aaa and of bbb.[5]▸ Answer▸ Official mark scheme← 2.13: Repeated positive integer root1.13: Factor and remainder on a cubic →