Additional Mathematics 0606 / Factors and polynomials / 2.92.9: Polynomial from given roots0606/22/M/J/20 — Question 4 · 5 marksMark as done · Save for later · Show all solutionsThe three roots of p(x)=0p(x) = 0p(x)=0, where p(x)=2x3+ax2+bx+cp(x) = 2x^{3} + ax^{2} + bx + cp(x)=2x3+ax2+bx+c are x=12x = \tfrac{1}{2}x=21, x=nx = nx=n and x=−nx = -nx=−n, where aaa, bbb, ccc and nnn are integers. The yyy-intercept of the graph of y=p(x)y = p(x)y=p(x) is 4. Find p(x)p(x)p(x), simplifying your coefficients.[5]▸ Answer▸ Official mark scheme← 2.2: Remainder and complete factorisation2.3: Factor theorem and factorisation →