Additional Mathematics 0606 / Factors and polynomials / 3.223.22: Binomial coefficient and term independent of yyy0606/11/O/N/24 — Question 5 · 4 marksMark as done · Save for later · Show all solutions(a)In the expansion of (1+kx)15(1 + kx)^{15}(1+kx)15, where kkk is a constant, the coefficient of x3x^{3}x3 is −29120-29120−29120. Find the value of kkk.[2]▸ Answer(b)Find the term independent of yyy in the expansion of (y8−2y2)12\left(\dfrac{y}{8} - \dfrac{2}{y^{2}}\right)^{12}(8y−y22)12.[2]▸ Answer▸ Official mark scheme← 3.21: Two cubics from an absolute-value graph3.23: Show a linear relation, then find aaa, bbb, ccc →
