3.10: Quadratic mapping inverse sketch and logarithmic composite

0606/12/O/N/23 — Question 8 · 9 marks

(a)(i)
It is given that f:x(3x+1)24f: x \mapsto (3x + 1)^{2} - 4 for xax \geqslant a, and that f1f^{-1} exists.
Find the least possible value of aa.
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(a)(ii)
Using this value of aa, write down the range of ff.
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(a)(iii)
Using this value of aa, sketch the graphs of y=f(x)y = f(x) and y=f1(x)y = f^{-1}(x) on the axes, stating the intercepts with the coordinate axes.
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(b)
It is given that
g(x)=ln(2x2+5)for x0,g(x) = \ln(2x^{2} + 5) \quad\text{for } x \geqslant 0,h(x)=3x2for x0.h(x) = 3x - 2 \quad\text{for } x \geqslant 0.
Solve the equation hg(x)=4hg(x) = 4 giving your answer in exact form.
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