Additional Mathematics 0606 / Indices and surds / 3.23.2: Surd quadratic equation0606/11/O/N/22 — Question 4 · 6 marksMark as done · Save for later · Show all solutionsDO NOT USE A CALCULATOR IN THIS QUESTION.Solve the equation (5−1)x2−2x−(5+1)=0(\sqrt{5} - 1)x^{2} - 2x - (\sqrt{5} + 1) = 0(5−1)x2−2x−(5+1)=0, giving your answers in the form a+b5a + b\sqrt{5}a+b5, where aaa and bbb are constants.[6]▸ Answer▸ Official mark scheme← 3.5: Square and rationalise a surd expression3.3: Quadratic with surd coefficients →
