Target Mathematics

3.114: Displacement s=(t+2)(42t)s=(t+2)(4-2t); motion graphs

0606/13/M/J/23 — Question 9 · 12 marks

(a)
A particle PP moves in a straight line with displacement s=(t+2)(42t)s=(t+2)(4-2t) for 0t50\leqslant t\leqslant 5. Find the values of tt for which the velocity is zero.
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(b)
On the axes, sketch the displacement–time graph of PP, stating the intercepts with the axes.
[3]
(c)
Sketch the velocity–time graph of PP, stating the intercepts.
[2]
(d)(i)
Find an expression for the acceleration of PP at time tt.
[1]
(d)(ii)
Hence sketch the acceleration–time graph of PP, stating the intercepts.
[2]