Additional Mathematics 0606 / Logarithmic and exponential functions / 1.31.3: Logarithmic equations with bases 3, 9 and 40606/11/M/J/19 — Question 7 · 8 marks · Log laws, Change of base, EquationsMark as done · Save for later · Show all solutions(a)Solve log3x+log9x=12\log_{3} x + \log_{9} x = 12log3x+log9x=12.[3]▸ Answer(b)Solve log4(3y2−10)=2log4(y−1)+12\log_{4}(3y^{2} - 10) = 2\log_{4}(y - 1) + \dfrac{1}{2}log4(3y2−10)=2log4(y−1)+21.[5]▸ Answer← 2.6: Exponential equation; lg equation with two factors1.8: Value of a two-term exponential expression →
