Additional Mathematics 0606 / Logarithmic and exponential functions / 2.32.3: Equation in lg x0606/21/O/N/16 — Question 3 · 5 marks · Log laws, EquationsMark as done · Save for later · Show all solutionsSolve the equation 2lgx−lg(x+102)=12\lg x - \lg\left(\dfrac{x + 10}{2}\right) = 12lgx−lg(2x+10)=1.[5]▸ Answer← 1.12: Simultaneous equations in log x and log y2.11: Equation in lg x (repeat) →