2.10: Index equation; solve log a b minus half equals log b a

0606/22/M/J/20 — Question 9 · 8 marks · Indices, Equations, Change of base

(a)
Solve the equation 95x27x2=243\dfrac{9^{5x}}{27^{x - 2}} = 243.
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(b)
logab12=logba\log_{a} b - \dfrac{1}{2} = \log_{b} a, where a>0a > 0 and b>0b > 0. Solve this equation for bb, giving your answers in terms of aa.
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