Additional Mathematics 0606 / Logarithmic and exponential functions / 2.142.14: Equation with powers of 2, matching indices0606/22/O/N/20 — Question 2 · 4 marks · Indices, EquationsMark as done · Save for later · Show all solutionsFind the value of xxx such that 4x+12x−1=32x/3×81/3\dfrac{4^{x+1}}{2^{x-1}} = 32^{x/3} \times 8^{1/3}2x−14x+1=32x/3×81/3.[4]▸ Answer← 2.7: Write as a single logarithm2.15: Bacteria model with constants P and Q — part (a) →
