3.46: Digit arrangements and a binomial coefficient equation

0606/11/M/J/21 — Question 6 · 9 marks

(a)(i)
Find how many different 5-digit numbers can be formed using the digits 1,3,5,6,81, 3, 5, 6, 8 and 99, with no digit used more than once.
[1]
(a)(ii)
How many of these 5-digit numbers are odd?
[1]
(a)(iii)
How many of these 5-digit numbers are odd and greater than 6000060\,000?
[3]
(b)
Given that 45×nC4=(n+1)n+1C545\times{}^{n}C_{4} = (n + 1)\,{}^{n + 1}C_{5}, find the value of nn.
[4]