Additional Mathematics 0606 / Quadratic functions / 2.102.10: Tangents to a quadratic curve0606/22/O/N/18 — Question 10 · 5 marksMark as done · Save for later · Show all solutionsTwo lines are tangents to the curve y=12−4x−x2y = 12 - 4x - x^{2}y=12−4x−x2. The equation of each tangent is of the form y=2k+1−kxy = 2k + 1 - kxy=2k+1−kx, where kkk is a constant.(i)Find the two possible values of kkk.[5]▸ Answer▸ Official mark scheme← 2.5: Tangent line to two quadratic curves2.14: Completing the square and a quartic equation →
